Question

I need the answer to the question

Answer 1

Answer: Following function gives the number of bacteria in a culture:

$n(t)=990e^{0.3t}\rightarrow(1)$

(a) The continues rate of growth can be found by taking the first time derivative of the equation (1), which is:

$\begin{gathered} R=\frac{dn(t)}{dt}=(0.3\times990)e^{0.3t} \\ R(t)=297e^{0.3t} \end{gathered}$

(b) The initial population can be found by plugging t = 0 in equation (1).

$\begin{gathered} n(0)=990e^{(0.3\times0)}=990 \\ n(0)=990 \end{gathered}$

THerefore the answer is 9

(c) At t = 5, the number of bacteria in the culture would be:

$\begin{gathered} n(5)=990e^{(0.3\times5)} \\ n(5)=990e^{(0.3\times5)} \\ n(5)=4,436.8721 \end{gathered}$

Or roughly 4437 bacteria.

Answer 2

Answer:

What question

Step-by-step explanation:

I'm all ears to help