The total moles of ions are released when the sample dissolves completely in water is 3.08 x 10⁻² mol of ions.
Each one mole of compound has Avogadro's number of molecules (6.022 x 10²³).
Find no. of moles of NiCl₂ by cross multiplication:
Let the number of moles be 'x'.
1.0 mol NiCl₂ → 6.022 x 10²³ molecules.
'x' mol NiCl₂ contains → 6.188 x 10²¹ molecules.
Thus, total moles of NiCl₂ = (1.0 mol)(6.188 x 10²¹ molecules)/(6.022 x 10²³ molecules)
Total moles of NiCl₂ = 1.028 x 10⁻² mol.
NiCl₂ is ionized as per the equation:
NiCl₂ → Ni²⁺ + 2Cl⁻.
That means 1.0 mol of NiCl₂ is ionized to form 3.0 moles (1.0 mol of Ni²⁺ and 2 moles of Cl⁻).
Thus, the total moles of ions that are released is 3.028 x 10⁻² mol.
To know more about the mole of the compound, here
https://brainly.com/question/18560111
#SPJ4
The complete question is-
How many total moles of ions are released when the following sample dissolves completely in water? 6.188 x 10 21 formula units of NiCl 2 a. 1.36 mol of ions b. 1.86 mol of ions c. 3.08 x 1022 mol of ions d. 0.0205 mol of ions e. 3.08 x 10-2 mol of ions