Please help me answer this question! :D It will be greatly appreciatedQuestion:Find the lateral surface area of the square pyramid.

In a square pyramid, the lateral surface area is given by the expression:
[tex]\text{Lateral surface area= (perimeter of base x slant height of pyramid)/2}[/tex]Then, the perimeter of the base is the sum of all sides:
Pb=4+4+4+4=16
Slant height of pyramid is 5 ft, then the lateral surface area is:
[tex]\begin{gathered} \text{LSA}=\frac{16\times5}{2} \\ \text{LSA}=\frac{80}{2}=40\text{ square f}eet \end{gathered}[/tex]