The interval for a normal distribution (bell-shaped) where we expect approximately 95% of the distribution to fall is given by:
[tex](\mu-2\sigma,\mu+2\sigma)[/tex]where μ is the mean and σ is the standard deviation of the distribution.
In this problem, we have:
[tex]\begin{gathered} \mu=62 \\ \sigma=12 \end{gathered}[/tex]Therefore, we expect approximately 95% of the distribution to fall in the interval:
[tex]\begin{gathered} (62-2\cdot12,62+2\cdot12) \\ \\ (62+24,62-24) \\ \\ (38,86) \end{gathered}[/tex]Thus, the answer is: from 38 to 86 jobs submitted per day.