We need to find the equation of the line that passes through the points (0,-9) and (6,1).
To solve it we're going to use the equation of a line given as:
[tex]y-y_0=m(x-x_0)[/tex]Where m represents the slope of the line and y0, x0 is any point of the line.
To find, firstly, the slope we're going to use the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{1-(-9)}{6-0}=\frac{10}{6}=\frac{5}{3}[/tex]Now, we reply to the slope in the equation line and chose any point from the ones given by the statement. To make easily the counts we can use (0,-9).
[tex]y-(-9)=\frac{5}{3}(x-0)[/tex][tex]y=\frac{5}{3}x-9[/tex]Then the correct answer for the equation of the line that passes through the points (0,-9) and (6,1) is:
[tex]y=\frac{5}{3}x-9[/tex]