The expression can be written as
[tex]5\log _{10}6+5\log _{10}7[/tex]Factoring out 5 gives
[tex]5(\log _{10}6+\log _{10}7)[/tex]Using the logarithm property that
[tex]\log _bx+\log _by=\log _bxy[/tex]we rewrite our expression as
[tex]5(\log _{10}6\times7)[/tex]Finally, using the other logarithm property that
[tex]a\log _bc=\log _bc^a[/tex]we rewrite our expression as
[tex]5(\log _{10}6\times7)=\textcolor{#FF7968}{(\log _{10}6^5\times7^5).}[/tex]which is choice b.