Question

Find the equation of the line that is perpendicular to the line y = 1/3x- 7 and passes through (1, -1).

Answer 1

Given:

$y=\frac{1}{3}x-7$

Slope of the given line is

$m_1=\frac{1}{3}$

Slope of the perpendicular line is

$m_2=-3$

Equation of line perpendicular to the given equation is

$\begin{gathered} y-y_1=m_2(x-x_1) \\ y+1=-3(x-1) \\ y+1=-3x+3 \\ y=-3x+3-1 \\ y=-3x+2 \end{gathered}$