Question

Find b and c so that y = 16x² + bx + c has vertex (0, - 5). b C =

Answer 1

In the equation:

y = 16x² + bx + c

the value of the leading coefficient, a, is equal to 16.

The equation of a parabola in vertex form is:

$y=a(x-h)^2+k$

where (h,k) is the vertex. Substituting with the vertex (0, -5) and a = 16, we get:

$\begin{gathered} y=16(x-0)^2-5 \\ y=16x^2-5 \end{gathered}$

In this equation, the values of b and c are:

b = 0

c = -5