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SOLUTION

QUestion 8

From the question, we have the foloowing dimentions given

[tex]\begin{gathered} \text{height}=24\text{inches } \\ \text{base}=48\text{inches, 60 inches } \end{gathered}[/tex]

Find the area of the trapeziod, we have

[tex]\text{Area of trapeziod=}\frac{1}{2}(\text{ sum of parallel )height }[/tex]

Then

[tex]\begin{gathered} =\frac{1}{2}(48+60)24 \\ =\frac{1}{2}\times(108)\times24 \\ =12\times108 \\ =1296in^2 \end{gathered}[/tex]

The area of the trapezoid is

[tex]1296in^2[/tex]

Since

[tex]\begin{gathered} 16in^2=1\text{tile } \\ \text{Then} \\ 1296in^2=x\text{ tile } \end{gathered}[/tex]

Hence

[tex]x=\frac{1296}{16}=81\text{tiles}[/tex]

Therefore,

There will be 81 tiles needed to cover the trapezoidal hearth

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