First let's write each equation using the slope-intercept form:
[tex]y=mx+b[/tex]So we have the following system:
[tex]\begin{cases}y=\frac{3}{2}x-4 \\ y=-\frac{3}{2}x+4\end{cases}[/tex]In order to solve this system, let's add both equation, this way we can find the value of y and then the value of x:
[tex]\begin{gathered} y+y=\frac{3}{2}x-4+(-\frac{3}{2}x)+4 \\ 2y=0 \\ y=0 \\ \\ 0=\frac{3}{2}x-4 \\ \frac{3}{2}x=4 \\ 3x=8 \\ x=\frac{8}{3} \end{gathered}[/tex]So the solution to this system is (8/3, 0), therefore the system has one solution.