Explanation
We are asked to get the length of the hypotenuse of the right triangle
To find the answer, we will make use of the trigonometric ratio
[tex]\begin{gathered} sin45=\frac{opposite}{hypotenuse}=\frac{6}{x} \\ \\ where \\ x=hypotenuse \end{gathered}[/tex]
If we cross multiply
[tex]\begin{gathered} x=\frac{6}{sin45} \\ \\ x=\frac{6}{\frac{1}{\sqrt{2}}} \\ \\ x=6\sqrt{2} \\ \end{gathered}[/tex]
Thus, the answer is
