Respuesta :

Answer:

D.

[tex]f(x)*g(x)=\frac{x-2}{x+6}[/tex]

Explanation:

Given:

Let's go ahead and simplify each of the functions as seen below;

[tex]\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12} \\ =\frac{x+12}{x^2+6x-2x-12} \\ =\frac{x+12}{x(x+6)-2(x+6)} \\ =\frac{x+12}{(x+6)(x-2)} \end{gathered}[/tex][tex]\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48} \\ =\frac{4(x^2-4x+4)}{4x+48} \\ =\frac{4(x^2-2x-2x+4)}{4x+48} \\ =\frac{4[x(x-2)-2(x-2)}{4x+48} \\ =\frac{4[(x-2)(x-2)]}{4(x+12)} \\ =\frac{(x-2)^2}{x+12} \end{gathered}[/tex]

Let's go ahead and multiply f(x) and g(x);

[tex]\begin{gathered} f(x)*g(x)=\frac{x+12}{(x+6)(x-2)}*\frac{(x-2)^{2}}{x+12} \\ f(x)*g(x)=\frac{x-2}{x+6} \end{gathered}[/tex]

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