Respuesta :

Quadratic Equation

A quadratic equation in the form:

[tex]ax^2+bx+c=0[/tex]

Can be solved by using the formula:

[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

We are given the function:

[tex]f(x)=3x^2-x+3[/tex]

We can identify the variables a=3, b=-1, c=3. Applying the formula:

[tex]x=\frac{-(-1)\pm\sqrt[]{(-1)^2-4\cdot3\cdot3}}{2\cdot3}[/tex]

Calculating:

[tex]\begin{gathered} x=\frac{1\pm\sqrt[]{1-36}}{6} \\ x=\frac{1\pm\sqrt[]{-35}}{6} \end{gathered}[/tex]

The square root of a negative number results in an imaginary quantity. Separating the roots and using the imaginary symbol i.

[tex]\begin{gathered} x_1=\frac{1}{6}+\frac{\sqrt[]{35}}{6}i \\ x_2=\frac{1}{6}-\frac{\sqrt[]{35}}{6}i \end{gathered}[/tex]

RELAXING NOICE
Relax