Please help! How can I solve this equation? Reminder: x = -2, y = -3, z = 5.

Given expression is
[tex]\frac{-z^2(1-2x)}{y-x}[/tex]Given
[tex]x=-2,y=-3,z=5[/tex]Substituting in the given expression,
[tex]\begin{gathered} \frac{-z^2(1-2x)}{y-x}=\frac{-(5)^2(1-2(-2))}{-3-(-2)} \\ =\frac{-25(1+4)}{-1} \\ =125 \end{gathered}[/tex]Hence, the value of the given expression is 125.