The acceleration of the jet when it speeds up = 7.5 m/s²
Explanation:The initial speed, u = 100 m/s
Distance travelled, s = 2. km
s = 2 x 1000m
s = 2000 m
Final speed, v = 200 m/s
The acceleration is found by using the equation of motion below
[tex]v^2=u^2+2as[/tex]Substitute v = 200 m/s, u = 100 m/s, s = 2000 m
[tex]\begin{gathered} 200^2=100^2+2\times a\times2000 \\ 40000=10000+4000a \\ 4000a=30000 \\ a=\frac{30000}{4000} \\ a=7.5m/s^2 \end{gathered}[/tex]The acceleration of the jet when it speeds up = 7.5 m/s²