Question

calculate the average rates of change from 2000 to 2009 and from 2009 ton2015. Round result to four decimal places?

Answer 1

Remember that

the average rate of change is equal to

$\frac{f(b)-f(a)}{b-a}$

where

f -----> is the population in thousands (dependent variable)

a and b -----> year (independent variable)

Part 1)

Average rate of change from 2000 to 2009

so

a=2000

b=2009

f(a)=f(2000)=844

f(b)=f(2009)=856

substutute the given values

$\frac{856-844}{2009-2000}=\frac{12}{9}=\frac{4}{3}=1.3333$

the average rate of change is 1.3333 thousands people per year

Part 2

Average rate of change from 2009 to 2015

we have

a=2009

b=2015

f(a)=f(2009)=856

f(b)=f(2015)=810

substitute

$\frac{810-856}{2015-2009}=\frac{-46}{6}=-\frac{23}{3}=-7.6667$

average rate is -7.6667 thousands people per year