Given the system of equations:
[tex]\begin{gathered} 6x+4y=7\rightarrow(1) \\ 6x+2y=5\rightarrow(2) \end{gathered}[/tex]
Subtract equation (2) from equation (1):
So,
[tex]\begin{gathered} (6x+4y)-(6x+2y)=7-5 \\ 4y-2y=2 \\ 2y=2 \\ y=\frac{2}{2} \\ y=1 \end{gathered}[/tex]
substitute with y into equation 1 to find x:
[tex]\begin{gathered} 6x+4=7 \\ 6x=7-4 \\ 6x=3 \\ \\ x=\frac{3}{6} \\ \\ x=\frac{1}{2} \end{gathered}[/tex]
So, the answer will be:
x = 1/2 y = 1
( x, y ) = ( 1/2 , 1 )
See the following picture:
