Respuesta :

First, let's look at the trigonometric ratios;

[tex]\sin \Theta=\frac{opposite}{hypotenuse}[/tex][tex]\cos \Theta=\frac{adjacent}{hypoteunse}[/tex][tex]\tan \Theta=\frac{opposite}{adjacent}[/tex]

Let's check each option and see if it is true

A.

[tex]\sec \Theta=\frac{1}{\cos \Theta}[/tex][tex]=\frac{1}{\frac{adjacent}{\text{hypotenuse}}}[/tex][tex]=\frac{hypotenuse}{\text{adjacent}}[/tex]

option A is not true

B

[tex]\csc \Theta=\frac{1}{\sin \Theta}[/tex][tex]=\frac{1}{\frac{opposite}{\text{hypotenuse}}}[/tex][tex]=\frac{hypotenuse}{\text{opposite}}[/tex]

option B is also not true

Option C is correct because

[tex]\sec \Theta=\frac{hypotenuse}{adjacent}[/tex]

D

[tex]\cot \Theta=\frac{1}{\tan \Theta}[/tex][tex]=\frac{1}{\frac{opposite}{\text{adjacent}}}[/tex][tex]=\frac{adjacent}{\text{opposite}}[/tex]

option D is not true

Hence, only option C is true

RELAXING NOICE
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