Step 1: Write out the formula for finding the z-score of a number
[tex]z=\frac{x-\mu}{\sigma}[/tex][tex]\begin{gathered} z=\text{ the z-score} \\ x=\text{ the number whose z-score we are looking for} \\ \mu=\text{ the mean of the distribution} \\ \sigma=the\text{ standard deviation of the distribution} \end{gathered}[/tex]Step 2: Find the z-score of 29
[tex]\begin{gathered} In\text{ this case,} \\ \mu=23,\sigma=5,x=29 \end{gathered}[/tex]Therefore,
[tex]z=\frac{29-23}{5}=\frac{6}{5}[/tex]Step 3: Find a score on Exam B that has a z-score 6/5
[tex]\begin{gathered} In\text{ this case,} \\ \mu=350,\sigma=20,x=\text{?} \end{gathered}[/tex]Therefore,
[tex]\frac{6}{5}=\frac{x-350}{20}[/tex]Cross-multiplying we have
[tex]\begin{gathered} 6\times20=5(x-350) \\ 120=5x-1750 \\ 120+1750=5x \\ 5x=1870 \\ x=\frac{1870}{5} \\ x=374 \end{gathered}[/tex]Hence, Sofia must score 374 marks in Exam B in order to do equivalently well as she did on Exam A