The depreciation equation is given by
[tex]f(x)=27000(0.86^x)[/tex]
where x represents the number of years. Here, the initial value of the car corresponds to x=0, then we have
[tex]\text{ initial value = f\lparen0\rparen=27000}[/tex]
After one year, the car value corresponds to x=1, that is,
[tex]\text{ after 1 year = f\lparen1\rparen=27000\lparen0.86}\rparen^1\text{=27000}\times0.86=\text{23220}[/tex]
Now, let's find the depreciation percentage by means of a rule of three:
[tex]\begin{gathered} 2700\text{ ----- 100 \%} \\ 23220\text{ ------- x} \end{gathered}[/tex]
so we have
[tex]x=\frac{23220\times100}{27000}=86\text{ \%}[/tex]
So the difference between 100% and 86% is 14% This means Nichole's car depreciate 14% each year