Respuesta :

Given data:

The initial velocity of the train is,

[tex]\begin{gathered} v_i=9\text{ miles/hour} \\ v_i=\frac{9}{2.237}\text{ m/s} \\ v_i=4.02\text{ m/s} \end{gathered}[/tex]

The final velocity of the train is,

[tex]undefined[/tex]

Solution:

The average acceleration of the train is,

[tex]a=\frac{v_f-v_i}{t}[/tex]

where v_f is the final velocity, v_i is the initial velocity, and t is the time taken,

Substituting the known values,

[tex]undefined[/tex]

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