The line is given by y=(-3/2)x-14.
The general equation of a straight line is y=mx+c, where m is the slope and c is the y intercept.
Comparing y=(-3/2)x-1 with y=mx+c, we find that the slope is m=-3/2.
The slope of a line that is perpendicular to the line with slope m is ,
M=-(1/m)
Hence, the slope of the perpendicular line is,
[tex]M=-\frac{1}{m}=\frac{-1}{\frac{-3}{2}}=\frac{2}{3}[/tex]Therefore, the slope of a line that is perpendicular to the line y = (-3/2)x - 14 is 2/3.
