Given:
The volume of the can, V=36.
The diameter of the can, D=4.
The can has the shape of a cylinder.
The radius of the can is,
[tex]\begin{gathered} r=\frac{D}{2} \\ =\frac{4}{2} \\ =2 \end{gathered}[/tex]The equation for the volume of a cylinder is,
[tex]V=\pi r^2h[/tex]Here, h is the height of the cylinder.
The volume of a cone that fits perfectly inside a cylinder has the same radius and the same height as the cylinder
The equation for the volume of a cone is,
[tex]V=\frac{1}{3}\pi r^2h[/tex]Therefore, the volume of the cone is 1/3 rd of the volume of the cylinder.
Hence, the volume of the cone can be found as,
[tex]\begin{gathered} V_c=\frac{V}{3} \\ =\frac{36}{3} \\ =12 \end{gathered}[/tex]Therefore, the volume of the cone is 12.
