We have to replace A= 25 mg in the equation and solve for t. Doing so, we have:
[tex]\begin{gathered} 25=50(0.9217)^t\text{ } \\ 0.5=(0.9217)^t\text{ (Dividing by 50 on both sides of the equation)} \end{gathered}[/tex][tex]\begin{gathered} \log _5(0.5)=\log _5(0.9217)^t(\text{ Taking the logarithm base 5 of both sides of the equation)} \\ \log _5(0.5)=t\cdot\log _5(0.9217)\text{ (Using the power rule of logarithms)} \\ -0.431=t\cdot(-0.0507)\text{ (Finding the logarithms for each case)} \\ 8.50=t\text{ (Dividing by }-0.0507\text{ on both sides of the equation)} \end{gathered}[/tex]The answer is 8.50 hours (Rounding to two decimal places)