ANSWER
0.02 m³
EXPLANATION
By the Archimedes' Principle, the weight of a floating object is equal to the weight of the water displaced by the object,
[tex]W_{\text{water displaced}}=W_{\text{canoe}}[/tex]
This is,
[tex]m_{\text{water}}g=m_{\text{canoe}}g[/tex]
We know that the weight of the canoe is 200N, so there is no need to find its mass. Also, the mass is the product of the density and the volume,
[tex]W_{\text{canoe}}=\delta_{water}\cdot V_{water}\cdot g[/tex]
The density of water is 1000 kg/m³, the acceleration due to gravity g is 9.8m/s² and the weight of the canoe is 200N. Solve for the volume of water,
[tex]V_{water}=\frac{W_{canoe}}{\delta_{water}\cdot g}=\frac{200N}{1000\operatorname{kg}/m^3\cdot9.8m/s^2}=0.02m^3[/tex]
Hence, the volume of water displaced by the canoe is 0.02m³.
