Respuesta :

Let's find the length of EF:

[tex]\begin{gathered} |EF|=\sqrt[]{(15-6)^2+(3-3)^2} \\ |EF|=9 \end{gathered}[/tex]

In order to find E'F', multiply EF by the scale factor, so:

[tex]\begin{gathered} |E^{\prime}F^{\prime}|=\frac{1}{3}|EF| \\ |E^{\prime}F^{\prime}|=\frac{1}{3}\cdot9 \\ |E^{\prime}F^{\prime}|=3 \end{gathered}[/tex]

Answer:

3

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