Respuesta :

Given that -6.6 is some number of times as large as 5.

Let x be the required number.

Given can be written as follows.

[tex]-6.6=5\times x[/tex][tex]\text{Use 6.6=}\frac{66}{10}\text{.}[/tex]

[tex]-\frac{66}{10}=5x[/tex]

Dividing by 5 into both sides, we get

[tex]-\frac{66}{10\times5}=\frac{5x}{5}[/tex]

[tex]-\frac{66}{50}=x[/tex]

Dividing 66 by 50, we get 1.32.

[tex]x=-1.32[/tex]

Hence the required number is -1.32.

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