Question

Using the equation from Part E (V=1/2πr↑2↓h), what is the approximate volume of one refraction cup? What is the relationship between this value and the value from Part D (V=50.24cm↑3)? Use 3.14 for pi.

Answer 1

Given:

The figure with diameter 8 cm and height 2 cm.

Required:

Find the volume.

Explanation:

We know the volume

$\begin{gathered} \text{ Volume = Area of semi-circular base}\times\text{ height} \\ \text{ Volume = }\frac{\pi r^2}{2}\times h \end{gathered}$

We have diameter 8 cm. So radius will be half that is 4 cm and height is 2 cm.

So,

$\begin{gathered} V=\frac{3.14\times4^2}{2}\times2 \\ V=50.24\text{ }cm^3 \end{gathered}$

Answer:

Hence, volume is 50.24 cm cube.