Question

A tv screen is 41 cm long and 31 cm high. the length of the diagonal is closest to

Answer 1

the length of the tv screen is,

l = 41 cm

the width of the tv is

b = 31 cm

the length of the diagonal will be the hypotenuse of the triangle,

so, diagonal length is,

$\text{diagonal}=\sqrt[]{41^2+31^2}$$\text{diagonal}=\sqrt[]{1681+961}$$\begin{gathered} \text{diagonal}=\sqrt[]{2642} \\ \text{diagonal}=51.04 \end{gathered}$

so, the length of the diagonal is closest 51.04 cm