Question

A parachutist's rate during a free fall reaches 198 kilometers per hour. What is this rate in meters per second? At this rate, how many meters will the parachutist
fall during 2 seconds free fall? Do not round your answers,

Answer 1

Step 1: Compute the rate in meters per seconds

$\begin{gathered} 1\operatorname{km}\text{ }=1000m \\ 1h=60\times60s \end{gathered}$

Therefore,

$\begin{gathered} 198\operatorname{km}\text{ / h }=\frac{198\operatorname{km}}{1h} \\ \text{Thus,} \\ 198\operatorname{km}\text{ / h }=\frac{198\times1000m}{60\times60s} \\ 198\operatorname{km}\text{ / h }=\frac{198\times10m}{6\times6s} \\ 198\operatorname{km}\text{ / h }=\frac{33\times10m}{1\times6s} \end{gathered}$

Hence,

$198\operatorname{km}\text{ / h }=\frac{11\times10m}{1\times2s}=55m\text{ /s}$

Therefore, the rate in meters per seconds is 55 m/s

Step 2: Compute the number of metes the parachutist will fall in 2s at this rate (55m/s)

At the rate of 55m/s, the distance the parachutist falls in 2s is given by

$55\times2=110m$

Hence, the number of meters is 110m