Question

I'm confused as to what formula I'm suppose to use for question number 6.) I got the wrong answer multiple times and the solution my teacher gave was 57.1 KPA

Answer 1

Combined gas law

$\text{ P}_1\text{V}_1\text{T}_2\text{ = P}_2\text{V}_2\text{T}_1$

T1= 200°C + 273.15 = 473.15 K

P1 = 101.3 kPa

V1 = 5L

T2 = 100°C + 273.16 = 373.15 K

V2 = 7L

Solve for P2

$\text{ P}_2\text{ =}\frac{\text{ P}_1\text{ V}_1\text{T}_2}{\text{ V}_2\text{ T}_1}=\text{ }\frac{101.3\text{ kPa }\times\text{ 5L }\times373.15\text{ K}}{7\text{ L }\times473.15\text{ K}}=\text{ 57.1 kPa}$

The answer is 57.1 kPa