Respuesta :

SOLUTION

Write out the equation

[tex]3x+2y=30[/tex]

The equation of a line in slope intercept form is given by

[tex]\begin{gathered} y=mx+c \\ \text{Where} \\ m=\text{slope c=intercept} \end{gathered}[/tex]

Hence

From the equation given, we make y the subject of the formula of the equation given.

[tex]\begin{gathered} 3x+2y=30 \\ \text{Subtract 3x from both sides } \\ 3x-3x+2y=30-3x \\ \text{Then} \\ 2y=-3x+30 \end{gathered}[/tex]

Divide both sides by 2

[tex]\begin{gathered} \frac{2y}{2}=\frac{-3x+30}{2} \\ \text{Then} \\ y=-\frac{3x}{2}+\frac{30}{2} \end{gathered}[/tex]

Hence

[tex]y=-\frac{3}{2}x+15[/tex]

Therefore

The equation of the line in slope intercept form is

y=-3/2x + 15

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