SOLUTION
Write out the equation
[tex]3x+2y=30[/tex]The equation of a line in slope intercept form is given by
[tex]\begin{gathered} y=mx+c \\ \text{Where} \\ m=\text{slope c=intercept} \end{gathered}[/tex]Hence
From the equation given, we make y the subject of the formula of the equation given.
[tex]\begin{gathered} 3x+2y=30 \\ \text{Subtract 3x from both sides } \\ 3x-3x+2y=30-3x \\ \text{Then} \\ 2y=-3x+30 \end{gathered}[/tex]Divide both sides by 2
[tex]\begin{gathered} \frac{2y}{2}=\frac{-3x+30}{2} \\ \text{Then} \\ y=-\frac{3x}{2}+\frac{30}{2} \end{gathered}[/tex]Hence
[tex]y=-\frac{3}{2}x+15[/tex]Therefore
The equation of the line in slope intercept form is
y=-3/2x + 15