Respuesta :

The equation given is

[tex]\frac{2}{5}(z+1)=y[/tex]

We need to solve for the variable "z".

First, we multiply the term "z + 1" by "2/5" and do a bit algebra to isolate "z".

The steps are shown below:

[tex]\begin{gathered} \frac{2}{5}(z+1)=y \\ \frac{2}{5}(z)+\frac{2}{5}(1)=y \\ \frac{2}{5}z+\frac{2}{5}=y \\ \frac{2}{5}z=y-\frac{2}{5} \\ z=\frac{y-\frac{2}{5}}{\frac{2}{5}} \end{gathered}[/tex]

We can simplify this a bit further:

[tex]\begin{gathered} z=\frac{y-\frac{2}{5}}{\frac{2}{5}} \\ z=\frac{y}{\frac{2}{5}}-\frac{\frac{2}{5}}{\frac{2}{5}} \\ z=\frac{5}{2}y-1 \end{gathered}[/tex]

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