Let x, and y represent the measures of the angles. Recall that the measure of two complementary angles adds up to 90°, therefore:
[tex]x+y=90.[/tex]We are given that:
[tex]x-y=48.[/tex]Solving the second equation for x, we get:
[tex]x=48+y.[/tex]Substituting the above equation in the first equation, we get:
[tex]48+y+y=90.[/tex]Solving for y, we get:
[tex]\begin{gathered} 48+2y=90, \\ 2y=90-48, \\ 2y=42, \\ y=\frac{42}{2}, \\ y=21. \end{gathered}[/tex]Now, substituting y=21 in the third equation, we get:
[tex]x=48+y=48+21=69.[/tex]Answer:
[tex]69^{\circ},\text{ and 21}^{\circ}.[/tex]