Question

Can you please help me with this trig ratios problem?

Answer 1

The expression is given

$\sin \theta=\frac{\sqrt[]{3}}{2}$

To determine the value of angle in degree.

$\theta=\sin ^{-1}(\frac{\sqrt[]{3}}{2})$$\theta=60^{\circ}$

Hence the value of angle in degree is 60 degree.