The initial speed of the rocket is u = 11 m/s
The mass of the rocket is m = 1.3 kg
The kinetic energy of the rocket will be
[tex]\begin{gathered} K\mathrm{}E\mathrm{}=\frac{1}{2}mu^2 \\ =78.65\text{ J} \end{gathered}[/tex]The kinetic energy will be converted to potential energy
[tex]KE=P\text{E}[/tex]Also, the potential energy will be
[tex]PE=\text{mgh}[/tex]Here, the acceleration due to gravity is g = 9.8 m/s^2
The height up to which the rocket will reach is h.
Substituting the values , the height will be
[tex]undefined[/tex]78.65