Respuesta :

The initial speed of the rocket is u = 11 m/s

The mass of the rocket is m = 1.3 kg

The kinetic energy of the rocket will be

[tex]\begin{gathered} K\mathrm{}E\mathrm{}=\frac{1}{2}mu^2 \\ =78.65\text{ J} \end{gathered}[/tex]

The kinetic energy will be converted to potential energy

[tex]KE=P\text{E}[/tex]

Also, the potential energy will be

[tex]PE=\text{mgh}[/tex]

Here, the acceleration due to gravity is g = 9.8 m/s^2

The height up to which the rocket will reach is h.

Substituting the values , the height will be

[tex]undefined[/tex]

78.65

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