What’s the answer for this problem? Please I’ve been stuck on this problem for literally an hour and I can’t solve it :(

Given:
In figure
there is a right angle triangle given with one side 16 unit and one angle 42 degree.
Required:
We need to find the value of x which is hypotenuse.
Explanation:
In this problem
we have to use the sin formula with angle 42 degree
[tex]\sin\emptyset=\frac{opp\text{ side}}{hypotenuse}[/tex]now put the values
[tex]\begin{gathered} \sin42=\frac{16}{x} \\ x=\frac{16}{0.6691}=23.9\approx24 \end{gathered}[/tex]Final answer:
The value of x is
[tex]x=23.9\approx24\text{ units}[/tex]