• A cone-shaped building is commonly used to storesand. What would be the volume of a cone-shapedbuilding with a diameter 50 m and height 20 m to thenearest tenth?») 52,333.3 m3) 13,083.3 m24,084.5 m33,804.1 m3

Respuesta :

Answer:

[tex]\boxed{13,083.3m^3}[/tex]

Explanation:

Step 1. The information we have about the cone is:

[tex]\begin{gathered} \text{Diameter:} \\ d=50m \\ Height\colon\text{ } \\ h=20m \end{gathered}[/tex]

Step 2. To find the Volume of the cone, we use the following equation:

[tex]V=\frac{\pi r^2h}{3}[/tex]

Where V is the volume, r is the radius and π=3.14.

To find r, we use:

[tex]r=\frac{d}{2}[/tex]

The value of the radius is:

[tex]\begin{gathered} r=\frac{50m}{2} \\ \downarrow \\ r=25m \end{gathered}[/tex]

Step 3. Substitute all of the values into the formula to find the Volume:

[tex]\begin{gathered} V=\frac{\pi r^2h}{3} \\ \downarrow \\ V=\frac{(3.14)(25m)^2(20m)}{3} \end{gathered}[/tex]

Solving the operations step by step:

[tex]\begin{gathered} V=\frac{(3.14)(625m^2)^{}(20m)}{3} \\ \downarrow \\ V=\frac{(3.14)(12,500m^3)}{3} \\ \downarrow \\ V=\frac{39,250m^3}{3} \\ \downarrow \\ V=13,083.333m^3 \end{gathered}[/tex]

Rounding to the nearest tenth (1 decimal):

[tex]13,083.3m^3[/tex]

Answer:

[tex]\boxed{13,083.3m^3}[/tex]

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