Given:
the distance of the tortoise is,
[tex]d=55\text{ m}[/tex]The coefficient of friction between the tyre and the asphault is,
[tex]\mu=0.82[/tex]The acceleration of the transport is,
[tex]\begin{gathered} a=-\mu g \\ =-0.82\times9.8 \\ =-8.04m/s^{2^{}} \end{gathered}[/tex]Now the final velocity after the brakes applied is 0.
we have to find the initial velocity.
we can write,
[tex]0^2=v^2-2ad[/tex]Substituting the values we get,
[tex]\begin{gathered} 0^2=v^2-2\times8.04\times55 \\ v=\sqrt[]{2\times8.04\times55} \\ v=29.7\text{ m/s} \end{gathered}[/tex]Hence the speed limit is 29.7 m/s.