Determine the equation of the line that passes through the point(-7,-1/3), and is perpendicular to the line y = -3x – 2.Enter your answer in slope-intercept form. EquationPls see picture

We will have the following:
First, since we need the line to be perpendicular we take the slope of the function given and find the slope of the line we want, that is:
[tex]m=-\frac{1}{(-3)}\Rightarrow m=\frac{1}{3}[/tex]Now, we find the line as follows:
[tex]y-(-\frac{1}{3})=\frac{1}{3}(x-(-7))\Rightarrow y+\frac{1}{3}=\frac{1}{3}x+\frac{7}{3}[/tex][tex]\Rightarrow y=\frac{x}{3}+2[/tex]So, the equation that we are looking for is:
[tex]y=\frac{x}{3}+2[/tex]