Question

Employees were asked how many times per week they exercised. The frequency table shows the results of the survey.

Answer 1

Solution

Total frequency = 5+10+2+9+33+12+15+3+1 = 90

(a) Create a probability distribution table

(b) P(x<4) =

$\begin{gathered} P(x<4)=p(x=1)+p(x=2)+p(x=3) \\ p(x<4)=\frac{5}{90}+\frac{10}{90}+\frac{2}{90}+\frac{9}{90} \\ =\frac{5+10+2+9}{90} \\ =\frac{26}{90} \\ =0.2889 \\ \approx0.29\text{ \lparen nearest hundredth\rparen} \end{gathered}$