Answer:
26.6 degrees.
Explanation:
A triangle diagram representing the given problem is attached below:
In the smaller right triangle:
• The side ,opposite to ,angle x = 20 ft
,
• The side ,adjacent to ,angle x = 40 ft
From trigonometric ratios:
[tex]\begin{gathered} \tan \theta=\frac{\text{Opposite}}{\text{Adjacent}} \\ \implies\tan x\degree=\frac{20}{40}=0.5^{} \end{gathered}[/tex]
We then solve for x.
[tex]\begin{gathered} x=\arctan (0.5) \\ x=26.565\degree \\ x\approx26.6\degree \end{gathered}[/tex]
The value of x is 26.6 degrees (to the nearest tenth of a degree).
