Question

evaluate the following expression when x=-4 and y=4x³-x /4y$\frac{x}{y}$

Answer 1

Answer

-15/4

Step-by-step explanation

Given the expression:

$\frac{x^3-x}{4y}$

Substituting x = -4 and y = 4:

$\begin{gathered} \frac{(-4)^3-(-4)}{4\cdot4}= \\ =\frac{-64+4}{16}= \\ =\frac{-60}{16}= \\ =-\frac{15}{4} \end{gathered}$