Given,
The measure of base of the triangle is 17.
The measure of Hypotenuse of the triangle is 19.
As, the triangle is right angled triangle.
By using Pythagoras theorem,
[tex](\text{perpendicular})^2=(\text{base})^2+(\text{perpendicular})^2[/tex]
Substituting the measure of the sides of the triangle,
[tex]\begin{gathered} 19^2=17^2+(\text{perpendicular})^2 \\ (\text{perpendicular})^2=19^2-17^2 \\ (\text{perpendicular})^2=361^{}-289 \\ (\text{perpendicular})^2=72 \\ \text{perpendicular})^{}=\sqrt{72} \\ \text{perpendicular}=8.49 \end{gathered}[/tex]
Hence, the measure of the perpendicular of the triangle is 8.49 (approx).
