The graph of the function f(x)=tan is given above for the interval x in[0,2 pi] Determine the one-sided limit . Then indicate the equation of the vertical asymptote .

Explanation
We are given the graph below of tan x:
We are required to determine limits and vertical asymptotes of the given limit.
This is achieved thus:
Limit: A limit is a value that the output of a function approaches as the input of the function approaches a given value.
Vertical Asymptote: A vertical asymptote is a vertical line that guides the graph of the function but is not part of it. It can never be crossed by the graph because it occurs at the x-value that is not in the domain of the function.
Therefore, we have:
[tex]\begin{gathered} \lim_{x\to(\frac{\pi}{2})^-}f(x)=\infty \\ \text{ We can deduce from the graph that as the function approaches }\frac{\pi}{2}\text{ from the left,} \\ \text{ the graph approaches positive infinity} \end{gathered}[/tex]This indicates the equation of the vertical asymptote as:
[tex]x=\frac{\pi}{2}[/tex]Also, we have:
[tex]\begin{gathered} \lim_{x\to(\frac{3\pi}{2})^-}f(x)=\infty \\ \text{ We can also deduce that as the function approaches }\frac{3\pi}{2}\text{ from the left, } \\ \text{ the graph approaches positive infinity} \end{gathered}[/tex]This indicates the equation of the vertical asymptote as:
[tex]x=\frac{3\pi}{2}[/tex]Hence, the answers review is:
[tex]\begin{gathered} \lim_{x\to(\frac{\pi}{2})^-}f(x)=\infty \\ Vertical\text{ }asymptote:x=\frac{\pi}{2} \\ \\ \lim_{x\to(\frac{3\pi}{2})^-}f(x)=\infty \\ Vertical\text{ }asymptote:x=\frac{3\pi}{2} \end{gathered}[/tex]