Question

The product of two consecutive odd integers is 420 more than three times the smaller integer.Find the integers?

Answer 1

We have

n first odd integer

n+2 next consecutive odd integer

So we have the next equation

$n(n+2)=3n+420$

So we need to find the value of n

$\begin{gathered} n^2+2n=3n+420 \\ n^2-n-420= \end{gathered}$

Then we need to solve the equation

$(n-21)(n+20)=$

The solutions of the equation are

n=21

n=-20

But as we want only odd solutions

n=21

n+2=23

ANSWER

The numbers are 21 and 23