Respuesta :

Given:

[tex]\sin x-\sin 3x[/tex]

Sol:.

Formula of sin3A is:

[tex]\sin 3A=3\sin A-4\sin ^3A[/tex]

Put the value of sin3x in given function:

[tex]\begin{gathered} =\sin x-\sin 3x \\ =\sin x-(3\sin x-4\sin ^3x) \\ =\sin x-3\sin x+4\sin ^3x \\ =-2\sin x+4\sin ^3x \\ =2\sin x(2\sin ^2x-1) \end{gathered}[/tex]

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