Answer:
B. a circle with center (0,3) and radius 4
Explanation:
Given the equation of the circle:
[tex]x^2+(y-3)^2=16[/tex]Compare it with the standard equation of a circle:
[tex](x-h)^2+(y-k)^2=r^2[/tex]We see that:
[tex]\begin{gathered} x^{}=x-h\implies h=0 \\ y-3=y-k\implies k=3 \\ r^2=16\implies r=4 \end{gathered}[/tex]The centre of the circle is:
[tex](h,k)=(0,3)[/tex]Therefore, the correct description is:
B. a circle with center (0,3) and radius 4