I need help will this besin A =a/c or the followingsin A =b/csin A =b/asin A =c/bsin A =c/asin A =a/csin A =a/b

In a right-angled triangle, the side facing the reference angle is the opposite side, the side facing the right angle is the hypotenuse
Since sinA= opposite/hypotenuse
opposite= a
hypotenuse = c
Thus, sinA= a/c