Question

A car of weight W=16000N rests on a surface that is part of a hydraulic lift system. The piston below the car has an area of 4E-1m^2. An input force F is applied to another piston of the hydraulic system; this piston's area is 4E-4m^2. What input force F is necessary to lift the car?

Answer 1

In order to calculate the force required, we can use the formula below:

$\frac{A_1}{A_2}=\frac{F_1}{F_2}$

Using F1 = 16000, A1 = 4*10^-1, F2 = F and A2 = 4*10^-4, we have:

$\begin{gathered} \frac{4\cdot10^{-1}}{4\cdot10^{-4}}=\frac{16000}{F}\\ \\ 10^3=\frac{16000}{F}\\ \\ F=\frac{16000}{10^3}\\ \\ F=16\text{ N} \end{gathered}$

Therefore the correct option is h.